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c^2+7c-120=0
a = 1; b = 7; c = -120;
Δ = b2-4ac
Δ = 72-4·1·(-120)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*1}=\frac{-30}{2} =-15 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*1}=\frac{16}{2} =8 $
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